Algorithm/noj.am
[Python] 백준 2504번 - 괄호의 값
SweetDev
2021. 7. 14. 15:09
# 2504 괄호의 값
str = input()
# 맞는지 검증
stack = []
for index, char in enumerate(str):
if char == '(':
stack.append('(')
elif char == '[':
stack.append('[')
elif char == ')':
if len(stack) > 0:
ret = stack.pop()
if ret != '(':
print("0")
exit(0)
else:
print("0")
exit(0)
elif char == ']':
if len(stack) > 0:
ret = stack.pop()
if ret != '[':
print("0")
exit(0)
else:
print("0")
exit(0)
if len(stack) !=0:
print("0")
exit(0)
# count 계산하기
out = ""
index = 0
char = ""
while True:
if index >= len(str):
# print(out)
print(eval(out))
exit(0)
char = str[index]
if char == "(" and (str[index + 1] == "(" or str[index + 1] == "["):
out += "+2*("
index += 1
elif char == "(" and str[index + 1] == ")":
out += "+2"
index += 2
elif char == "[" and (str[index + 1] == "(" or str[index + 1] == "["):
out += "+3*("
index += 1
elif char == "[" and str[index + 1] == "]":
out += "+3"
index += 2
elif char == ")":
out += ")"
index += 1
elif char == "]":
out += ")"
index += 1